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Click here👆to get an answer to your question ️ Find the expansion of the following (x y 2)^3 Join / Login > 9th > Maths > Polynomials > Algebraic Identities > Find the expansion of the f maths Find the expansion of the following (x y 2) 3 Easy Answer (x y 2) 3 Let us simplify the expression By using the formula, we get (x y 2) 3 = (x y) 2 3 = (x y) 3 (2How to expand the following > $\log (x y)$ Ask Question Asked 8 years, 7 months ago Active 8 years, 7 months ago Viewed 31k times 5 1 $\begingroup$ I know for a fact that it is not $\log x \log y$, but Im unsure as to how to proceed I have checked the basic log properties but nowhere do they give an example of a statement like the one above Thanks in advance logarithmsExpand each of the following, using suitable identities (i) (x 2 y 4 z) 2 (ii) (2 x − y z) 2 (iii) (− 2 x 3 y 2 z) 2 (iv) (3 a − 7 b − c) 2 (v) (− 2 x 5 y − 3 z) 2 (vi) 4 1 a − 2 1 b 1 2

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Expand the following (1/x y/3)^3

Expand the following (1/x y/3)^3-Simplify the following y3x72xy 6d7c4c6 5f92d7f answers 1) 5x 7, variable y there has no more value so its ok if you will not write it all you Definition binomial A binomial is an algebraic expression containing 2 terms For example, (x y) is a binomial We sometimes need to expand binomials as follows (a b) 0 = 1(a b) 1 = a b(a b) 2 = a 2 2ab b 2(a b) 3 = a 3 3a 2 b 3ab 2 b 3(a b) 4 = a 4 4a 3 b 6a 2 b 2 4ab 3 b 4(a b) 5 = a 5 5a 4 b 10a 3 b 2 10a 2 b 3 5ab 4 b 5Clearly, doing

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Mathematics RS Agarwal Standard IX Q 1 Expand each of the following, using suitable identities (i) ( x 2 y 4 z) 2 (ii) ( 2 x − y z) 2 (iii) ( − 2 x 3 y 2 z) 2 (iv) ( 3 a − 7 b − c) 2 (v) ( − 2 x 5 y − 3 z) 2 (vi) 1 4 a − 1 2 b 1 2 Expand (1/x y/3) whole cube asked in Class XI Maths by navnit40 Expert (404k points) polynomials 1 vote 1 answer The polynomial p{x) = x4 2x3 3x2 ax3a7 when divided by x1 leaves the remainder 19 asked in Class IX Maths by ashu Expert (98k points) polynomials 0 votes 1 answer Expand the following (4ab 2c)2 asked Jan 30,50 K views 34 K people like this Like Share Share Answer Text Answer 2 log x 3log y 4 log z Related Video

 Expand the first two brackets (x −y)(x − y) = x2 −xy −xy y2 ⇒ x2 y2 − 2xy Multiply the result by the last two brackets (x2 y2 −2xy)(x − y) = x3 − x2y xy2 − y3 −2x2y 2xy2 ⇒ x3 −y3 − 3x2y 3xy2 Always expand each term in the bracket by all the other terms in the other brackets, but never multiply two or Find an answer to your question Expand the following a) 3(x 5) b) 4(x4) c) 2(5x 1) d) 7(x9y)Remove the brackets from the following expressions a) 5(x4) b) 2(y − 3) c) 4(3−a) d) x(2x) e) p(q 3) f) −3(2a) g) s(t− s) h) −2(b−3) i) 5a(2b3c) j) −y(2x− 5y) k) 4(x2y −3z) l) −2a(3a−5b2c) 2 Simplify the following expressions a) 52(x1) b) 3x4(2x− 1) c) 6a− 3(a2) d) x2 − x(1x) e) 12c−5(2c− 1) f) 4(y 3)− 2y g) 5pq − p(2− p) h) 7r 2(34r) i

Solution Steps (x1) (x3) ( x 1) ( x 3) Apply the distributive property by multiplying each term of x1 by each term of x3 Apply the distributive property by multiplying each term of x 1 by each term of x 3 x^ {2}3xx3 x 2 3 x x 3 Combine 3x and x to get 4x Combine 3 x and x to get 4 xBy using standard formulae, expand the following (1 to 9) 1 (i) (2x 7y) 2 (ii) (1/2 x 2/3 y) 2 Solution (i) (2x 7y) 2 It can be written as = (2x) 2 2 × 2x × 7y (7y) 2 So we get = 4x 2 28xy 49y 2 (ii) (1/2 x 2/3 y) 2 It can be written as = (1/2 x) 2 2 × ½x 2/3y (2/3 y) 2 So we get = ¼ x 2 2/3 xy 4/9 y 2 2 (i) (3x 1/2x) 2 (ii) (3x 2 y 5z) 2 SolutionExpand the following `(i) (3a2b)^(3) (ii) ((1)/(x)(y)/(3))^(3)` (iii) `(4(1)/(3x))^(2)`

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 Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries Students (upto class 102) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (MainsAdvance) and NEET can ask questions from any subject and get quick answers by2 x 3 2a = _____ Sometimes you need to write an expression as a single logarithm Use the rules to work backwards Example 6 Write 2 log 3 x log 3 y as a single logarithm log 3 x 2 log 3 y Use the Power Rule for Logarithms to move the 2 in 2 log 3 x to the exponent of x = log 3 x 2y Use the Product Rule for Logarithms The answer is 2log 3Expand the following `(i) (3a2b)^(3) (ii) ((1)/(x)(y)/(3))^(3)` (iii) `(4(1)/(3x))^(2)` class9;

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 x^3y^33x^2y3xy^23x^23y^26xy3x3y1 This binomial has the form (ab)^3 We expand the binomial by applying this property (ab)^3=a^33a^2b3ab^2b^3 Where in given binomial a=x and b=y1 We have x(y1)^3= x^33x^2(y1)3x(y1)^2(y1)^3 remark it as (1) In the above expand we still have two binomials to expand (y1)^3 and (y1)^2 For (y1)^3 we3(x2) = 3x6 Example Expand x(x− y) The x outside must multiply both terms inside the brackets x(x− y) = x2 −xy Example Expand −3a2(3− b) Both terms inside the brackets must be multi plied by −3a2 −3a 2(3−b) = −9a 23a b Example Expand (x5)x Here, the brackets appear first, but the principle is the same Both terms inside must be multiplied by the x outside (x5)x Find the expansion of the following (xy1) whole cube Share with your friends Share 0

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1 Expand each of the following, simplifying the coefficient in each term a (1 x)4 5b (1 – x) c (1 4x)3 d (1 – 2y)3 e (1 1 2 x)4 2f (1 1 3 y)3 4g (1 x)5 h (1 – 3 2 x) 2 Expand each of the following, simplifying the coefficient in each term 3a (x y) b (a – b)5 c (x 2y)4 d (2 y)3 e (3 – x)3 f (5 2x)4 g (3 – 4y)5 h (3 1 2 x)4 3 Find the first four terms in theFind an answer to your question Expand And Simplify The Following (x3)(x3)(3x2) (2x1)(x2)(x3) (x3)(2x1)(3x2) legolover111ovs0il legolover111ovs0il Mathematics Middle School answered Expand And Simplify The Following (x3)(x3)(3x2) (2x1)(x2)(x3) (x3)(2x1)(3x2) 2 See answers Advertisement Advertisement TeslaElectric Please Answer the Following= expand the following ( 1/x y/3 )^3 Ask for details ;

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√ expand the following (1/x y/3)^3 Expand the following (1/xy/3)^3 ⋅(1)3−k ⋅(−x)k ∑ k = 0 3 ⁡ The program enables the user to avoid tedious exercises in simplification, expansion, and manipulation of algebraic expressions For example, rather than spending odious amounts of time using the distributive property, Mathematica allows the user to quickly discover that \( (x1Expand the following logx^(2)y^(3)z^4 Apne doubts clear karein ab Whatsapp par bhi Try it now CLICK HERE 1x 15x 2x Loading DoubtNut Solution for you Watch 1000 concepts & tricky questions explained!Subtract eq 3 from eq 1 to get y = 3 Substitutute our value for y into eq 2 for simplicity x 3 = 3 therefore x = 6 Process of substitution Add y to the right hand side of equation 2 to get x = 3 y Substitute this expression of x into equation 1 to eliminate x 3(3y) 2y = 12 Expand and simplify 9 y = 12 therefore y = 3

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